Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

I have $_SERVER['HTTP_REFERER'] — pretend it is http://example.com/i/like/turtles.html. What would I need to do to get just the http://example.com part out of the string, and store it in its own variable?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
297 views
Welcome To Ask or Share your Answers For Others

1 Answer

In this example, the best solution would be to use PHP's parse_url method. This splits up the URL into an associative array. You would then build your final value by combining the scheme with the host:

if ( $parts = parse_url( "http://example.com/i/like/turtles.html" ) ) {
    echo $parts[ "scheme" ] . "://" . $parts[ "host" ];
}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share

548k questions

547k answers

4 comments

86.3k users

...