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I'm using jQuery to show/hide a div by clicking on the show/hide buttons. However, my code doesn't work because every time it returns to the way it was before when I click on my buttons. I'm almost sure that this is due to a page reload, because every time I click on a button it reloads the page.
Does anybody know what could be the reason behind this?

Here is the important chunk of code:

<form role="form" method="post" action="./something.php">
  ...
  <button id="hidemultmachines" onclick="$('#multmachines').hide(); $(this).hide(); $('#showmultmachines').show();">
    Hide section below ...
  </button>
  <button id="showmultmachines" onclick="$('#multmachines').show(); $(this).hide(); $('#hidemultmachines').show();">
    ... Create multiple entries
  </button>
  <div id="multmachines">
    ...
  </div>
  <div>
    <div>
      <input type="hidden" name="total" value="{ $smarty.section.i.total }">
      <button type="submit" name="Submit" value="Save">Save</button>
    </div>
  </div>
</form>

And this is my jQuery code in the header:

$(document).ready(function(){
    $('#hidemultmachines').hide();
    $('#multmachines').hide();
}

When I put the buttons outside the form it works. Why?

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1 Answer

That's because your button elements have no type specified, and by default button elements have their type set to "submit". When you click one of the buttons, they attempt to submit your form. Simply specifying a type of "button" will fix this:

<button type="button" class="close" id="hidemultmachines" onclick="..."></button>

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