c++ - sizeof character array for a dynamically created array

Question

I need to create a char array dynamically based on the pattern length, i.e., plen. However, when I do sizeof(table), I get 8. Why am I getting 8 instead of 3?

int main() {
    char *pattern = "aaa";
    int plen = strlen(pattern);
    char *table = new char[plen + 1];
    for(int i = 0; i < plen; i++) {
        table[i] = pattern[i];
    }
    cout << sizeof(table) << plen << table;
    return 0;
}

The output I get is 83aaa...: 8 for sizeof(table), 3 for plen and aaa for table, which has the stored value of pattern.

Answer 1

It is because table is a pointer, not an array. And the size of a pointer in your architecture is 8 bytes.