Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

im using a canvas to visualize a small game of mine. Basicly i have two objects that represent space ships, each of them has a "Location" array which holds the ships current x/y. According to these arrays, i drawImage on the canvas (totalw/h is 300/300 fyi).

Now, for the difficult part. i want to draw animations (gunfire) on that canvas. basicly from ship1 x/y to ship2 x/y.

For the animation function itself, im passing an effects object that holds 3 Arrays, shooter.location[x, y], target.location[x, y] and a third array that holds where the EFFECT is currently at [x, y].

this.animateEffects = function(effects){

    var shooter = effects.shooter;
    var target = effects.target;
    var current = effects.current;

    var canvas = document.getElementById("effects");
    var context = canvas.getContext("2d");
        context.clearRect(0, 0, canvas.width, canvas.height);
        context.beginPath();
        context.fillStyle = "red";
        context.arc(current[0], current[1], 5, 0, 2*Math.PI);
        effects.current[0]++
        effects.current[1]++
        context.fill();

        if (current == target){
            console.log("ding");
            this.end()
        }
}

My "problem" is that im, if possible at all, looking for a smart way to determine (for each frame) if effects[x, y] should go ++ or -- or a combination of the two, depending on where the "moving" ships are located at (at the time, the shooting started).

Any advise or hints are appreciated.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
198 views
Welcome To Ask or Share your Answers For Others

1 Answer

You can fire a bullet from shooter to target using linear interpolation.

  1. Calculate the difference in the original X & Y positions of the shooter and target.

    // save the starting position of the bullet (== shooter's original position)
    // (these original X & Y are needed in the linear interpolation formula)
    bulletOriginalX=shooter.x;
    bulletOriginalY=shooter.y;
    
    // calc the delta-X & delta-Y of the shooter & target positions
    // (these deltas are needed in the linear interpolation formula)
    dx=target.x-shooter.x;
    dy=target.y-shooter.y;
    
  2. Move the bullet towards the target using the interpolation formula

    // where percent == the percent you want the bullet to be between 
    // it's starting & ending positions
    // (between starting shooter & starting target positions)
    currentBulletX=bulletOriginalX+dx*percent;
    currentBulletY=bulletOriginalY+dy*percent;
    

Here's an example:

var canvas=document.getElementById("canvas");
var ctx=canvas.getContext("2d");
var cw=canvas.width;
var ch=canvas.height;

shooter={x:50,y:50};
target={x:100,y:100};
effect={x:50,y:50,dx:0,dy:0,pct:0,speedPct:0.25};

draw();
fire();

$('#test').click(function(){
  moveEffect();
  draw();
});

function fire(){
  effect.x=shooter.x;
  effect.y=shooter.y;
  effect.dx=target.x-shooter.x;
  effect.dy=target.y-shooter.y;
  effect.pct=0;
}

function moveEffect(){
  effect.pct+=effect.speedPct;
}

function draw(){
  ctx.clearRect(0,0,cw,ch);

  ctx.beginPath();
  ctx.arc(shooter.x,shooter.y,15,0,Math.PI*2);
  ctx.closePath();
  ctx.strokeStyle='green';
  ctx.stroke();

  ctx.beginPath();
  ctx.arc(target.x,target.y,15,0,Math.PI*2);
  ctx.closePath();
  ctx.strokeStyle='red';
  ctx.stroke();

  if(effect.pct>1){return;}

  var x=effect.x+effect.dx*effect.pct;
  var y=effect.y+effect.dy*effect.pct;

  ctx.beginPath();
  ctx.arc(x,y,3,0,Math.PI*2);
  ctx.closePath();
  ctx.fillStyle='black';
  ctx.fill();

}
body{ background-color: ivory; padding:10px; }
#canvas{border:1px solid red;}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<button id=test>Animate 1 frame</button>
<br><canvas id="canvas" width=300 height=300></canvas>

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...