Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

I have a table called players as follows:

First_Id    Second_Id     Name
1           1             Durant
2           1             Kobe
1           2             Lebron
2           2             Dwight
1           3             Dirk

I wish to write a select statement on this table to retrieve all rows whose first ids and second ids match a bunch of specified first and second ids.

So for example, I wish to select all rows whose first and second ids are as follows: (1,1), (1,2) and (1,3). This would retreive the following 3 rows:

First_Id    Second_Id    Name
1           1            Durant
1           2            Lebron
1           3            Dirk

Is it possible to write a select query in a manner such as:

SELECT * 
FROM PLAYERS
WHERE (First_Id, Second_Id) IN ((1,1), (1,2) and (1,3))?

If there is a way to write the SQL similar to the above I would like to know. Is there a way to specify values for an IN clause that represents multiple rows as illustrated.

I'm using DB2.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
361 views
Welcome To Ask or Share your Answers For Others

1 Answer

This works on my DB2 (version 9.7 on Linux/Unix/Windows) by using this syntax:

SELECT *
FROM PLAYERS
WHERE (First_Id, Second_Id) IN (VALUES (1,1), (1,2), (1,3))

This syntax won't work on DB2 on the Mainframe (at least in version 9.1) because you can't substitute a sub-select with a VALUES expression. This syntax will work:

SELECT *
FROM PLAYERS
WHERE (First_Id, Second_Id) IN (SELECT 1, 1 FROM SYSIBM.SYSDUMMY1 UNION ALL
                                SELECT 1, 2 FROM SYSIBM.SYSDUMMY1 UNION ALL
                                SELECT 1, 3 FROM SYSIBM.SYSDUMMY1)

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...