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I have a table with the an array column type:

 title       tags
"ridealong";"{comedy,other}"
"ridealong";"{comedy,tragedy}"
"freddyjason";"{horror,silliness}"

I would like to write a query that produces a single array per title(in an ideal world it would be a set/deduplicated array)

e.g.

select array_cat(tags),title from my_test group by title

The above query doesn't work of course, but I would like to produce 2 rows:

"ridealong";"{comedy,other,tragedy}"
"freddyjason";"{horror,silliness}"

Any help or pointers would be very much appreciated (I am using Postgres 9.1)


Based on Craig's help I ended up with the following (slightly altered syntax since 9.1 complains about the query exactly as he shows it)

SELECT t1.title, array_agg(DISTINCT tag.tag) 
FROM my_test t1, (select unnest(tags) as tag,title from my_test) as tag 
where tag.title=t1.title
GROUP BY t1.title;
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1 Answer

Custom aggregate

Approach 1: define a custom aggregate. Here's one I wrote earlier.

CREATE TABLE my_test(title text, tags text[]);

INSERT INTO my_test(title, tags) VALUES
('ridealong', '{comedy,other}'),
('ridealong', '{comedy,tragedy}'),
('freddyjason', '{horror,silliness}');

CREATE AGGREGATE array_cat_agg(anyarray) (
  SFUNC=array_cat,
  STYPE=anyarray
);

select title, array_cat_agg(tags) from my_test group by title;

LATERAL query

... or since you don't want to preserve order and want to deduplicate, you could use a LATERAL query like:

SELECT title, array_agg(DISTINCT tag ORDER BY tag) 
FROM my_test, unnest(tags) tag 
GROUP BY title;

in which case you don't need the custom aggregate. This one is probably a fair bit slower for big data sets due to the deduplication. Removing the ORDER BY if not required may help, though.


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