Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

suppose you have a simple web page that dynamically loads content that looks like this:

- main.html -

<!DOCTYPE html>
<html xmlns="https://www.w3.org/1999/xhtml">
<head>
<script type="text/javascript"
   src="https://ajax.aspnetcdn.com/ajax/jquery/jquery-1.6.2.js">
</script>
<script type="text/javascript">
$(function() {
    $.ajax({
         type: 'get', cache: false, url: '/svc.html',
         success: function(h) {
             $('#main').html(h);
         }
    });
});
</script>
</head>

<body>
    <div id='main'>
    loading...
    </div>
</body>
</html>

and that the page it loads uses a little Javascript in a separate file:

- svc.html -

<script type="text/javascript"
   src="https://ajax.aspnetcdn.com/ajax/jquery/jquery-1.6.2.js">
</script>
<script type="text/javascript" src="/plugin.js" css="/plugin.css"></script>
<div id='inner'>
dynamically loaded content
</div>

notice the css attribute on the script tag - it indicates a style-sheet that belongs to the script and which the script will load for us. Here's the script:

- plugin.js -

var css = $('<link />', {
    rel: "stylesheet", type: "text/css", href: $('script:last').attr('css')
});
$('head').append(css);

and, finally, the style-sheet, which merely colours the inner div that gets loaded, as proof that it all works:

- plugin.css -

#inner
{
    border: solid 1px blue;
}

now, you'll notice the way the style-sheet gets loaded: we look at $('script') and pick off the last one, then we grab the css attribute and attach a link item to the head of the document.

I can visit /svc.html and the javascript runs, loads my style-sheet, all's cool - however, if I visit /main.html, the javascript runs but fails to find the loading of the plugin.js in the array of $('script') (and therefore fails to load the stylesheet). Note that the plugin script does run, it just doesn't see itself.

Is this a bug? a limitation of the jQuery AJAX method? shouldn't $('script') reflect all scripts that have been loaded?

* edit *

after much wailing and gnashing of teeth, I decided to go for Kevin B's solution, however, I can't get it to work, basically because the plugin.js code runs at the time the scriptNode gets inserted, but within the plugin code, the node has not yet been inserted and is thus not available in the $('script') array - so I'm still SOL. I've put all the code for review here:

http://www.arix.com/tmp/loadWithJs/

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
161 views
Welcome To Ask or Share your Answers For Others

1 Answer

The jQuery code that adds HTML to the DOM always strips out <script> tags. It runs them and then throws them away.

An exception to that behavior is when you use "$.load()" with the hack that allows you to load a fragment of a page:

$.load("http://something.com/whatever #stuff_I_want", function() { ... });

In that case, the scripts are stripped and not evaluated/run.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share

548k questions

547k answers

4 comments

86.3k users

...