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This was recently asked to a friend in an interview and we do not know of any solution other than the simple O(n3) one.

Is there some better algorithm?

The question is to find all triplets in an integer array whose sum is less than or equal to given sum S.

Note: I have seen other such problems on SO with performance O(n2log n) but all of them were solving the easier version of this problem like where arr[i] + arr[j] + arr[k] = S or where they were only checking whether one such triplet exists.

My question is to find out all i,j,k in arr[] such that arr[i] + arr[j] + arr[k] <= S

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From a worst-case asymptotic perspective, there is no better algorithm since the size of the output is potentially O(n3).

e.g. Let the array be the numbers 1 through n. Let S = 3n. Clearly, any subset of three array elements will be less than S and there are (n choose 3) = O(n3) subsets.

There are a few ways you can speed up non-worst cases though. For example, try sorting the array first. That should give you some hints.


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