Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

How do I properly escape the quotes in the -param value in the following command line?

$cmd="\serveroto.exe -batch=B -param="sort1;parmtxt='Security ID=1234'""
Invoke-Expression $cmd 

This of course fails. I tried to escape the quotes (single and double) using the escape character ` and did various combination, but nothing is working.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
877 views
Welcome To Ask or Share your Answers For Others

1 Answer

Using the backtick (`) works fine for me if I put them in the following places:

$cmd="\serveroto.exe -batch=B -param=`"sort1;parmtxt='Security ID=1234'`""

$cmd returns as:

\serveroto.exe -batch=B -param="sort1;parmtxt='Security ID=1234'"

Is that what you were looking for?

The error PowerShell gave me referred to an unexpected token 'sort1', and that's how I determined where to put the backticks.

The @' ... '@ syntax is called a "here string" and will return exactly what is entered. You can also use them to populate variables in the following fashion:

$cmd=@'
"\serveroto.exe -batch=B -param="sort1;parmtxt='Security ID=1234'""
'@

The opening and closing symbols must be on their own line as shown above.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...