Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

I am having following lines of code.

sysLoader = (URLClassLoader)Thread.currentThread().getContextClassLoader();
url = sysLoader.getResource("tempFile.txt");

It is giving an weird problem. If I run this from a path where there is no space in the path (Folder names) then it is running fine. But if the path contains any spaces (line "c:New Foler...") then it is not working.

How to solve this?

EDIT: In more detail - I inspected the sysloader object.

sysloader -> UCP -> path

Is having a path with character %20 instead of space

And therefore all the URLs are null.

How to resolve this?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
656 views
Welcome To Ask or Share your Answers For Others

1 Answer

This is known by Sun/Oracle, their advice is to use URI objects which will remove the %20 characters:

Instead of doing this:

FileInputStream fis = new FileInputStream(url.getFile());

you can force any %-escaped characters to be decoded by first converting the URL to a URI, and then use the path component of the URI as the filename:

URI uri = new URI(url.toString());
FileInputStream fis = new FileInputStream(uri.getPath());

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...