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现在有一个数组,结构是这样的:

[0:"简单:10:5"
1:"一般:5:10"
2:"困难:2:20"]

怎么分别取出 “简单:10:5” ?

最终的结果是要这样计算的:

类别为“简单”的题有10道, 每道题5分;“一般”的题目有5道,每道题10分;“困难”的题有2道,每道题20分。这样可计算出“总计”=10+5+2=17,“满分”=10*5 + 5*10 + 2*20 = 140。

谢谢!搞不清楚 [0:"简单:10:5"] 这样的数据结构到底是什么类型的,要怎么做?


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1 Answer

没错,压根没有这种类型,所以这里我假如你的数据源是字符串,那么:

let re = /"([^:]+):([^:]+):([^:]+)"/g,
    m,
    res = [];
while (m = re.exec(data)) {
    let item = {
        type: m[1],
        num: +m[2],
        score: +m[3]
    };
    res.push(item);
    // 总计  val += item.num;
    // 满分  full += (item.num * item.score);
}

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