django - How can I upload multiple files to a model field?

Question

I want to upload multiple files through a ModelForm,with all files to be assigned to a file field of the Model.I have gone through the docs and I saw an example on it and I ve implemented it here but I can only get my form to pick multiple files but only one get saved and assigned to filesfield.Below are my codes

models.py

class Feed(models.Model):
    user=models.ForeignKey(User,on_delete=models.CASCADE,related_name='feeds')
    text=models.TextField(blank=False,max_length=500)
    files = models.FileField(upload_to="files/%Y/%m/%d")

forms.py

class FeedForm(ModelForm):
    class Meta:
        model=Feed
        fields=('text','auth','files')
        widgets={"files":forms.FileInput(attrs={'id':'files','required':True,'multiple':True})}

and views.py

def post_feed(request):
    form_class = FeedForm
    if request.method == 'POST':
        form = form_class(request.POST,request.FILES)
        if form.is_valid():
            feed = form.save(commit=False)
            feed.user = User.objects.get(pk=1)
            feed.pub_date=timezone.now()
            #instance = Feed(files=request.FILES['files'])
           # feed.files=request.FILES['files']
            feed.save()
            return redirect('home')
    else:
        form = form_class()
        return render(request, 'post_feed.html', {'form': form,})

from django.views.generic.edit import FormView
from .forms import FeedForm

class FileFieldView(FormView):
    form_class=FeedForm
    template_name='post_feed.html'
 '''success_url=???   #I dont know what to write here.I thought of putting this
render(request, 'post_feed.html', {'form': form,}) because I just want 
to reload the page but it gave an error,so I removed it entirely.'''

    def post_feed(self,request,*args,**kwargs):
        form_class=self.get_form_class()
        form=self.get_form(form_class)
        filez=request.FILES.getlist('files')
        if form.is_valid():
            for f in filez:
                f.save()
            return self.form_valid(form)     
        else:
            return self.form_invalid(form) 

Kindly help me out,Thanks in advance.

Answer 1

You have to create a separate model for the files and connect them with a foreign key:

class Feed(models.Model):
    user=models.ForeignKey(User, on_delete=models.CASCADE, related_name='feeds')
    text=models.TextField(blank=False, max_length=500)


class FeedFile(models.Model):
    file = models.FileField(upload_to="files/%Y/%m/%d")
    feed = models.ForeignKey(Feed, on_delete=models.CASCADE, related_name='files')

I hope this helps.