escaping - Ignore percent sign in batch file

Question

I have a batch file which moves files from one folder to another. The batch file is generated by another process.

Some of the files I need to move have the string "%20" in them:

move /y "\myservermyfolderfile%20name.txt" "\myserverotherfolder"

This fails as it tries to find a file with the name:

\myservermyfolderfile0name.txt

Is there any way to ignore %? I'm not able to alter the file generated to escape this, such as by doubling percent signs (%%), escaping with / or ^ (caret), etc.

Answer 1

You need to use %% in this case. Normally using a ^ (caret) would work, but for % signs you need to double up.

In the case of %%1 or %%i or echo.%%~dp1, because % indicates input either from a command or from a variable (when surrounded with %; %variable%)

To achieve what you need:

move /y "\myservermyfolderfile%%20name.txt" "\myserverotherfolder"

I hope this helps!