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QueryWrapper<Menu> queryWrapper = new QueryWrapper<>();
queryWrapper.select("menu_id","parent_id", "menu_name").eq("is_menu", 1);
queryWrapper.orderByAsc("sort");
return getBaseMapper().selectList(queryWrapper);

这段代码中,只返回3个字段。

{
    "menuId": 3,
    "parentId": 1,
    "menuName": "商品管理",
    "status": null,
    "isMenu": null,
    "sort": null,
    "updatetime": null,
    "addtime": null,
}

其他未select的字段都为null.
有什么办法可以不用返回这些未select的字段吗?


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1 Answer

@JsonInclude(NONNULL)


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