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I'm trying to find last business day of of the month. I wrote the code below for that and it works fine but I was wondering if there is a cleaner way of doing it?

from  datetime import date,timedelta
import datetime
import calendar

today=datetime.date.today()

last = today.replace(day=calendar.monthrange(today.year,today.month)[1])

if last.weekday()<5:
    print last

else:
    print last-timedelta(days=1+last.weekday()-5)

Thanks in advance!

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I use the following:

from pandas.tseries.offsets import BMonthEnd
from datetime import date

d=date.today()

offset = BMonthEnd()

#Last day of current month
offset.rollforward(d)

#Last day of previous month
offset.rollback(d)

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