In x86 assembly language, is there any way to obtain the upper half of the EAX
register? I know that the AX
register already contains the lower half of the EAX
register, but I don't yet know of any way to obtain the upper half.
I know that mov bx, ax
would move the lower half of eax
into bx
, but I want to know how to move the upper half of eax
into bx
as well.